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x^2+0.894x-0.0876=0
a = 1; b = 0.894; c = -0.0876;
Δ = b2-4ac
Δ = 0.8942-4·1·(-0.0876)
Δ = 1.149636
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.894)-\sqrt{1.149636}}{2*1}=\frac{-0.894-\sqrt{1.149636}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.894)+\sqrt{1.149636}}{2*1}=\frac{-0.894+\sqrt{1.149636}}{2} $
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